Which order arranges liquids from least to greatest viscosity?

o2, c3h8, h2o, c24h50

c24h50, c3h8, h2o, o2

o2, h2o, c3h8, c24h50

c3h8, h2o, c24h50, o2

I think the correct answer is the first option. The correct order of the liquids from least to greatest viscosity would be O2, C3H8, H2O, C24H50. Liquid oxygen would be the substance with the least viscosity since it has the bonds present is weakest as compared to the other substances. C24H50 would have the greatest viscosity as it has the most bonds present and would be much stronger to break. Comparing the viscosities of water and C3H8, we would find that C3H8 would be less viscous with as value of  5.38x10^-6 Pa-s and for water, 8.90 × 10−4 Pa-s. Comparing the bonds of water and C3H8, water would have stronger bonds due to hydrogen bonding.

we need an equation that would relate the concentration of the original solution to that of the desired solution.  to solve this we use the equation expressed as follows, 

m1v1 = m2v2

where m1 is the concentration of the stock solution, v1 is the volume of the stock solution, m2 is the concentration of the new solution and v2 is its volume.

m1v1 = m2v2

0.266 m x v1 = 0.075 m x 150 ml

v1 = 42.29 ml

therefore, we need about 42.29 ml of the 0.266 m of lithium nitrate solution to make 150.0 ml of the 0.075 m lithium nitrate solution.