Which statement about is true? it is zero for any compound in its standard state. it is positive when the bonds of the product store more energy than those of the reactants. it is negative when a compound forms from elements in their standard states. it is zero for any element that is in the liquid state.

i would say b

explanation:

but i think i would need more information than that

Only 10 mole of water will react with 10 mole of Na metal

and produce

                     10Na + 10H₂O > 10NaOH + 5H₂

Explanation:

2Na + 2H₂O > 2NaOH + H₂

Exothermic Reaction:

This reaction is supper exothermic and when sodium metal react with water it produce a lot of heat.

Limiting Reagent:

Limiting reagent is the amount of reactant in a chemical reaction that determines the amount of products that will be produce.

For instance we will use the same equation

2Na + 2H₂O > 2NaOH + H₂

The reaction shows that 2 mole of sodium combine with 2 mole of water and will produce 2 mole of NaOH and 1 mole of Hydrogen gas.

if we increase the amount of  water  to 4 mole then the same amount of product will form, and the extra water will remain unracted.

Similarly if we increase amount of Na to 4 mole then only 2 mole will react and will produce same amount.

Now

if we add 10 mole of Na to a large Volume of water following thing will happen

Given Reaction:

                  2Na + 2H₂O > 2NaOH + H₂

Data from Reaction:

                   2Na +  2H₂O > 2NaOH + H₂

                   2 mole   2mole                   2mole      1mole

Applying unity formula:

2 mole of Na will react with 2mole of water

So

                       2 mole of Na ≅ 2mole of H₂O

                       10 mole of Na = 10 mole of H₂O

So the same reaction will occur and produce NaOH and hydrogen gas

So, From the above reaction

                          2 mole of Na ≅ 2mole of NaOH

if 2 mole of Na produces 2 mole of NaOH then 10 mole will produce how much NaOH

apply the unity formula

2 mole of the Na ≅ 2 mole of NaOH

10 mole of the Na ≅ X mole of NaOH

so by cross multiplication

2 mole of Na x X mole of NaOH ≅ 2 mole of NaOH x 10 mole of the Na

we have to find moles of NaOH so by rearrangement of the above equation

X mole of NaOH = 2 mole x 10 mole

                                       2 mole

X mole of NaOH= 10 mole

So

10 mole of Na will produce 10 mole NaOH

For Hydrogen Gas that produce :

                         2 mole of Na ≅ 1 mole H₂

If 2 mole of Na produces 1 mole of H₂ then 10 mole will produce how much H₂

apply the unity formula

2 mole of the Na ≅ 1 mole of H₂

10 mole of the Na ≅ X mole of H₂

so by cross multiplication

2 mole of Na x X mole of H₂ ≅ 1 mole of H₂ x 10 mole of the Na

we have to find moles of H₂ so by rearrangement of the above equation

X mole of H₂ = 1 mole x 10 mole

                                       2 mole

X mole of H₂ = 5 mole

So

The following will be reaction if 10 moles Na thrown in large volume of water

Only 10 mole of water will react with it

                     10Na + 10H₂O > 10NaOH + 5H₂ and heat