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allytrujillo20oy0dib
23.12.2020 •
Chemistry
Which substance is the limiting reactant when 12 g of sulfur reacts with 18 g of oxygen and 24 g of sodium hydroxide according to the following chemical equation?
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Ответ:
NaOH is the limiting reactant
Further explanationGiven
12 g of sulfur reacts with 18 g of oxygen and 24 g of sodium hydroxide
Required
The limiting reactant
Solution
Reaction
2 S(s) + 3 O₂(g) + 4 NaOH(aq) ⇒ 2 Na₂SO₄(aq) + 2 H₂O(l)
mol S(MW=32.065 g/mol) :![\tt \dfrac{12}{32.065}=0.374](/tpl/images/1006/2858/e9e23.png)
mol O₂(MW=32 g/mol)![\tt \dfrac{18}{32}=0.5625](/tpl/images/1006/2858/86a68.png)
mol NaOH(MW=40 g/mol)A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and the smallest ratio becomes a limiting reactant
S : O₂ : NaOH =
Ответ:
D. the amount of heat absorbed or released when a solid dissolves
Explanation: