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qwemnb7401
28.11.2019 •
Chemistry
Which substance is the limiting reactant when 4.0 g of sulfur reacts with 6.0 g of oxygen and 8.0 g of sodium hydroxide according to the following chemical
2 s(s) + 3 o2(g) + 4 naoh(aq) → 2 na2so4(aq) + 2 h2o(l)
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Ответ:
Limiting reactant is NaOH
Explanation:
In the reaction:
2S(s) + 3O₂(g) + 4NaOH(aq) → 2Na₂SO₄(aq) + 2H₂O(l)
4.0 g of sulfur, 6.0 g of oxygen and 8.0 g of sodium hydroxide are:
4,0g S×
= 0,125 moles S
6,0g O₂×
= 0,188 moles O₂
8,0g NaOH×
= 0,2 moles NaOH
For a complete reaction of 0,2 moles of NaOH you will need:
0,2 mol NaOH×
= 0,1 moles of Sulfur
0,2 mol NaOH×
= 0,15 moles of Oxygen
As you have 0,125 moles of S and 0,188 moles of O₂ that are more than moles you need for a complete reaction of NaOH, limiting reactant is NaOH
I hope it helps!
Ответ:
polystyrene
Explanation:
it weighs less and is able to float on water, an aluminum wood slate would sink in water