WILL GIVE BRANLIEST 1)how many liters of HCl are produced when 47.2 L of chlorine are reacted with excess hydrogen at STP

2)if you need to make 24.0 g LiOH , how many grams of Li3N must you react with excess water?

3)How many moles of hydrogen gas can be produced from 13.2 moles of hydrochloric acid (HCl)

4)if 34.9g of copper (ll) chloride reacts with 42.1g of sodium nitrate what is the limiting reactant?

(i) 0.261 moles of HCl, (ii) 0.131 moles of and (iii) 12.5 grams of

Explanation: The balanced equation for the formation of HCl by the reaction magnesium chloride with water is:

From above balanced equation, there is 1:2 mol ratio between magnesium chloride and HCl.

As per the given information, 5.85 L of HCl gas is produced. here, temperature and pressure is not mentioned, so let's assume STP conditions.

At STP, volume of 1 mol of a gas is 22.4 L. With the help of this, we can calculate the moles of HCl present in 5.85 L.

= 0.261 mol HCl

As there is 1:2 mol ratio between magnesium chloride and HCl, we can calculate the moles of magnesium chloride from the above calculated moles of HCl as:

= 0.131 mol

Molar mass of magnesium chloride is given as 95.2 gram per mol. On multiplying the moles by molar mass we can calculate its mass reacted.

= 12.5 g