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rachelsweeney10
07.07.2019 •
Chemistry
Would it take 5 cell divisions for one original cell to produce 128 new cells?
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Ответ:
Yes, it will take 5 cell divisions for one original cell to produce 128 cells.
Ответ:
Explanation: Here, we will be considering 1 cup is equal to 1 mol.
2 water + sugar + lemon juice → 4 lemonade
Moles of water present in 946.36 g of water![=\frac{946.36 g}{236.59 g/mol}=4 mol](/tpl/images/0483/7297/4d957.png)
Moles of sugar present in 196.86 g of water![=\frac{196.86 g}{225 g/mol}=0.8749 mol](/tpl/images/0483/7297/2da8a.png)
Moles of lemon juice present in 193.37 g of water![=\frac{193.37 g}{257.83 g/mol}=0.7499 mol](/tpl/images/0483/7297/45d10.png)
Moles of lemonade in 2050.25 g of water![=\frac{2050.25 g}{719.42 g/mol}=2.8498 mol](/tpl/images/0483/7297/fdade.png)
As we can see that number of moles of lemon juice are limited.
So, we will consider the reaction will complete in accordance with moles of lemon juice.
1 mole lemon juice reacts with 2 mol of water,then 0.7499 mol of lemon juice will react with:
Mass of water used = 1.4998 mol × 236.59 g/mol=354.8376 g
Water remained unused = 946.36 g - 354.8376 g =591.5223 g
1 mole lemon juice reacts with mol of sugar,then 0.7499 mol of lemon juice will react with:
Mass of sugar used = 0.7499 mol × 225 g/mol = 168.7275 g
Sugar remained unused = 196.86 g - 28.1325 g
1 mole of lemon juice gives 4 moles of lemonade.
Then 0.7499 mol of lemon juice will give:
Mass of lemonade obtained = 2.996 mol × 719.42 g/mol = 2157.9722 g
Theoretical yield of lemonade = 2157.9722 g
Experimental yield of lemonade = 2050.25 g
Percentage yield of lemonade:
The percentage yield of lemonade is 95% and ingredient which remained unused were water and sugar.