Write a balanced equation state the reaction type, and perform the requested stoichiometry: Carbon and hydrogen combine to form methane. How many grams of carbon would be needed to react with 30.2 grams of hydrogen?
Solved
Show answers
More tips
- S Science and Technology How to Secure Exam Sessions: Silence Mobile Phones in the Classroom...
- G Goods and services How to Choose a Bread Maker?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
- S Society and Politics How Could Nobody Know About the Dead Mountaineers?...
- H Health and Medicine How to Cure Adenoids?...
- H Health and Medicine Why Wearing a Back Brace Can Be Beneficial During Back Strain?...
- S Sport When and Where Will the 2014 World Cup be Held?...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
Answers on questions: Chemistry
- M Mathematics Which of the following is equal to g(x)?...
- P Physics Someone please help! Given that 10000cm^3 of a fluid flows through a 2cm diameter pipe in 10 minutes:(a) Find the fluid rate of flow in cubic meters per second. (b) Calculate...
- M Mathematics Mark simplified three over five ÷ five over eight; his work is shown below. Identify where he made his error. Original division problem: three over five ÷ five over eight...
Ответ:
C + 2H2 = CH4
Given 30.2g of H2
Find the Moles
Mole =Mass/Molar Mass
Molar Mass of H2 = 1x2 = 2g/mol
Mole = 30.2/2
= 15.1moles of Hydrogen gas.
Now from the balanced equation of Reaction above...
1mole of Carbon reacts completely with 2moles of Hydrogen gas.
"x" moles of carbon with react with 15.1moles of Hydrogen
x = 15.1/2
=7.55moles of carbon.
We now have moles of carbon.
To find mass
Mole =Mass/Molar Mass
Mass = Mole x Molar Mass
Molar mass of carbon = 12g/mol
Mass = 7.55 x 12
Mass = 90.6g of carbon is needed.
Ответ:
T₂ = 478.93 K
Explanation:
Given that,
Initial pressure, P₁ = 178 kPa
Initial temperature, T₁ = 37°C = 310 K
Final pressure, P₂ = 275 kPa
We need to find the new temp of the air in the tire, assuming the volume is constant. We know that,
So, the new temperature is equal to 478.93 K.