Write structural formulas for each of the following: (a) 1-Heptene (g) 1-Bromo-3-methylcyclohexene (b) 3-Ethyl-2-pentene (h) 1-Bromo-6-methylcyclohexene (c) cis-3-Octene (i) 4-Methyl-4-penten-2-ol (d) trans-1,4-Dichloro-2-butene (j) Vinylcycloheptane (e) (Z)-3-Methyl-2-hexene (k) 1,1-Diallylcyclopropane (f) (E)-3-Chloro-2-hexene (l) trans-1-Isopropenyl-3-methylcyclohexane

Answer is: sulfuric acid is the limiting reactant.
Chemical reaction: 3H₂SO₄ + 2Al(OH)₃ → Al₂(SO₄)₃ + 6H₂O.
m(H₂SO₄) = 34 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 34 g ÷ 98 g/mol.
n(H₂SO₄) = 0,346 mol.
m(Al(OH)₃) = 33 g.
n(Al(OH)₃) = 33 g ÷ 78 g/mol.
n(Al(OH)₃) = 0,423 mol.
From chemical reaction: n(H₂SO₄) : n(Al(OH)₃) = 3 : 2.