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monster5368

monster5368

13.11.2019 •

Chemistry

You will need to have the following calculations prepared for the lab. calculate how many ml of the 7.0 × 10−5 m allura red stock solution will be needed to prepare 10.00 ml of the following solutions. show your work for one example. 3.5 × 10−5 m 2.8 × 10−5 m 2.1 × 10−5 m 1.4 × 10−5 m 3.5 × 10−6 m

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Ответ:

prettyprincess9643

09.01.2022

a) 5.0 ml

b) 4.0 ml

c) 3.0 ml

d) 2.0 ml

e) 0.50 ml

Explanation:

According to the dilution law:

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = $7.0\times 10^{-5}$ M

V_1 = volume of stock solution = ?

M_2 = molarity of diluted solution = $3.5\times 10^{-5}$ M

V_2 = volume of diluted solution = 10.00 ml

$7.0\times 10^{-5}\times V_1=3.5\times 10^{-5}\times 10.00$

V_1=5.0ml

b) $2.8\times 10^{-5}$ M

$7.0\times 10^{-5}\times V_1=2.8\times 10^{-5}\times 10.00$

V_1=4.0ml

c) $2.1\times 10^{-5}$ M

$7.0\times 10^{-5}\times V_1=2.1\times 10^{-5}\times 10.00$

V_1=3.0ml

d) $1.4\times 10^{-5}$ M

$7.0\times 10^{-5}\times V_1=1.4\times 10^{-5}\times 10.00$

V_1=2.0ml

e) $3.5\times 10^{-6}$ M

$7.0\times 10^{-5}\times V_1=3.5\times 10^{-6}\times 10.00$

V_1=0.50ml

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Ответ:

sduquesnay23ocesdcom

19.02.2023

An atom having 52 protons and 54 electrons would have an atomic number of 52 and a net charge of -2. This element would be 52 Te 2-, or choice A.

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