Zad.2. Napisz wzory sumaryczne poniższych związków: a) siarczek chromu (VII)
b) tlenek złota (III)
c) bromek żelaza (III)
d) chlorek sodu
Prosze

Molecular mass of C₂H₄ is,

M = 2×12 + 4×1 g/mol

M = 28 g/mol

Moles of C₂H₄ in 5.6 g of C₂H₄ :

n = 5.6/28 mol

n = 0.2 mol

Now, 1 mol of C₂H₄ contains 2 moles of carbon.

So, number of moles of carbon are :

n = 0.4 mol

We know, 1 mol of any atom contains 6.022 × 10²³ atoms.

So, number of carbon atoms are :

Hence, this is the required solution.