bernadetteindre6650
05.05.2020 •
Computers and Technology
The variable grade can have any real number value from 0 to 100. Ask the user to enter a grade in numerical form. Write an if-elseif-else statement that displays the letter grade (any format) corresponding to a numerical grade in an appropriately formatted output statement. Use the standard 10-point grading scale: a: A: 90 ≤ grade a: B: 80 ≤ grade < 90 a: C: 70 ≤ grade < 80 a: D: 60 ≤ grade < 70 a: F: grade < 60
Solved
Show answers
More tips
- L Leisure and Entertainment Couchsurfing: A New Way to Travel...
- G Goods and services Which TV is better - LCD or Plasma?...
- S Sport How to Learn to Pull Up on Monkey Bars?...
- L Leisure and Entertainment Scrapbooking: What is it and Why is it Becoming More Popular?...
- C Computers and Internet Where did torrents.ru move to?...
- B Business and Finance Understanding Cash Flow: What It Is and How It Works...
- C Computers and Internet What Are Peers and Seeds in Torrenting?...
- H Health and Medicine 10 Simple Techniques on How to Boost Your Mood...
- G Goods and services How to Choose the Right High Chair for Your Baby?...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
Answers on questions: Computers and Technology
- C Computers and Technology Is an open source system designed to allow one workstation to remotely manipulate and receive screen updates from another workstation....
- M Mathematics What s -4/9 x 5/8 has to be in fraction and simplified...
- M Mathematics The function f(x) is defined below. What is the end behavior of f(x)? f(x) = –288 + 46x2 – 4x3 – 2x4 + 48x 0 0 as x 700, f(x) → and as x +-, f(x) +- as x +, f(x) → and as -00,...
- M Mathematics Can someone please help me? i got this answer wrong the first try and i really need guidance on how to do this Angle T = ___ degrees...
Ответ:
See explaination
Explanation:
#include <iostream>
using namespace std;
int main()
{
float marks;
cout<<"Enter your grade value :";
cin>>marks;
if(marks>=90)
cout<<"Your grade is 'A'";
else if(marks>=80&& marks<90)
cout<<"Your grade is 'B'";
else if(marks>=70&& marks <=80)
cout<<"Your grade is 'C'";
else if(marks>=60&& marks <70)
cout<<"Your grade is 'D'";
else
cout<<"Your grade is 'F'";
}
Ответ:
i would join but imma doing school rn so i cant