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skyemichellec
26.10.2020 •
Computers and Technology
Write the SQL queries that accomplish the following tasks in the HAFH Realty Company Property Management Database:
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Ответ:
The complete question is:
Write the SQL queries that accomplish the following tasks in the HAFH Realty Company Property Management Database:
a. Display the SMemberID and SMemberName for all staff members.
b. Display the CCID, CCName, and CCIndustry for all corporate clients.
c. Display the BuildingID, BNoOfFloors, and the manager’s MFName and MLName for all buildings.
d. Display the MFName, MLName, MSalary, MBDate, and number of buildings that the manager manages for all managers with a salary less than $55,000.
e. Display the BuildingID and AptNo, for all apartments leased by the corporate client WindyCT.
f. Display the InsID and InsName for all inspectors whose next inspection is scheduled after 1-JAN-2014. Do not display the same information more than once.
g. Display the SMemberID and SMemberName of staff members cleaning apartments rented by corporate clients whose corporate location is Chicago. Do not display the same information more than once.
h. Display the CCName of the client and the CCName of the client who referred it, for every client referred by a client in the music industry.
i. Display the BuildingID, AptNo, and ANoOfBedrooms for all apartments that are not leased.
Also a schema of the HAFH database is attached.
Using SQL's SELECT, FROM, WHERE syntax, find below the queries for each question.
a.
SELECT SMemberID , SMemberName
FROM staffmember
b.
SELECT CCID, CCName, CCIndustry
FROM corpclient
c.
SELECT b.BuildingID, b.BNoOfFloors, m.MFName, m.MLName
FROM building b, manager m
WHERE b.ManagerID = m.ManagerID
d.
SELECT m.MFName, m.MLName, m.MSalary, m.MBDate, count(*) as buildings
FROM building b, manager m
WHERE m.MSalary<55000
AND b.ManagerID = m.ManagerID
GROUP BY m.ManagerID
e.
SELECT b.BuildingID, a.AptNo
FROM building b, apartment a, corpclient c
WHERE c.CCName = "WindyCT"
AND c.CCID = a.CCID
AND a.BuildingID = b.BuildingID
f.
SELECT DISTINCT i.InsID, i.InsName
FROM inspector i, inspecting x
WHERE i.InsID = x.InsID
AND x.DateNext > "2014-01-01"
g.
SELECT DISTINCT s.SMemberID, s.SMemberName
FROM staffmember s, cleaning c, apartment a, corpclient cc
WHERE s.SmemberID = c.SmemberID
AND c.AptNo = a.AptNo
AND a.CCID = cc.CCID
AND cc.CCLocation = "Chicago"
h.
SELECT cc1.CCName, cc2.CCName
FROM corpclient cc1, corpclient cc2
WHERE cc1.CCIDReferencedBy = cc2.CCID
AND cc2.CCIndustry = "Music"
i.
SELECT a.BuildingID, a.AptNo, a.ANoOfBedrooms
FROM apartment a
WHERE a.CCID NOT IN (SELECT c.CCID FROM corpclient c)
Ответ:
answer:
ab-cd+c=a
step-by-step explanation: