Engineering: Based on following data, angular acceleration of the tibia 450 rad/sec 2 the mass moment of inertia for the tibia is 0.40 nm sec 2 the perpendicular distance between patellar tendon and the center of rotation is 0.045m determine the muscle force acting on patellar tendon. show all works

Based on following data, angular acceleration of

hawleyemily

31.12.2021

4000 N

Explanation:

We have given angular acceleration $\alpha =450rad/sec^2$

Moment of inertia = 0.40 Nm

The distance d from the center of rotation is d=0.045 m

We have to find the muscle force F

From torque equation we know that $Fd=I\alpha$

$F\times 0.045=0.40\times 450$

$F=4000\ N$

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scasemere

13.09.2022

GM Crankshaft Keyway. Used for keying lower timing chain gears as well as harmonic balancers!

Explanation:

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