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22.04.2020 •
Engineering
If the products of a certain reaction are favored (i.e., the Δ G value of the reaction is negative), one would expect a significant amount of product to form when the reactants are combined. Which of the choices could explain why such a reaction might produce very little product?
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Ответ:
B. high Ea
The available choices are as below:
A. low Ea
B. high Ea
C. positive AH
D. negative AS
Explanation:
ΔG is a measure of how favorable a reaction is, it also relates to the equilibrium constant. It is also the measure of spontaneity of a chemical reaction.
A reaction with a negative ΔG, is very favorable.
A reaction with a positive ΔG is not favorable.
A reaction with ΔG = 0 is at equilibrium.
Now a molecule must acquire sufficient activation energy before they can react. However, the higher the activation energy, the slower the chemical reaction will be which leads to production of very little product.
Ответ:
C++ program is explained below
Explanation:
#include <iostream>
#include <cmath>
#include <iomanip>
#include <string>
using namespace std;
int main(){
string shape;
double height;
double width;
double radius;
const double PI = 3.1416;
double length;
cout << "Enter the shape type: (rectangle, circle, cylinder) ";
cin >> shape;
cout << endl;
if (shape == "rectangle"){
cout << "Enter the length of the rectangle: ";
cin >> length;
cout << endl;
cout << "Enter the width of the rectangle: ";
cin >> width;
cout << endl;
cout << "Perimeter of the rectangle = "<< 2 * (length + width) << endl;
cout << "Area of the rectangle = "<< length * width << endl;
}
else if (shape == "circle"){
cout << "Enter the radius of the circle: ";
cin >> radius;
cout << "Area of the circle = "<< PI * pow(radius, 2.0) << endl;
cout << "Circumference of the circle: "<< 2 * PI * radius << endl;
cout << endl;
}
else if (shape == "cylinder")
{
cout << "Enter the height of the cylinder: ";
cin >> height;
cout << endl;
cout << "Enter the radius of the base of the cylinder: ";
cin >> radius;
cout << endl;
cout << "Surface area of the cylinder: " << 2 * PI * radius * height + 2 * PI * pow(radius, 2.0)<< endl;
cout << "Volume of the cylinder = "<< PI * pow(radius, 2.0)* height << endl;
}
else
cout << "The program does not handle " << shape << endl;
cout << fixed << showpoint << setprecision(2);
return 0;
}