If the cos of angle x is eight seventeenths and the triangle was dilated to be two times as big as the original, what would be the value of the cos of x for the dilated triangle? Clue: Use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no spaces.

8/17

Explanation:

The cos of angle x is eight seventeenth and the triangle was dilated to be two times as big as the original:

Cos x = 8/17

Let the original triangle be ∆ABC

Dilated triangle be ∆DEF

Find attached the diagram.

All sides of the triangle are scaled by the same factor when we apply a dilation.

DE = 2 × AB

EF = 2 × BC

DF = 2 × AC

∠A = ∠D

∠B = ∠E

∠C = ∠F

Dilation also known as scaling does not affect angle measure. The angle measures remain the same.

Therefore, The value of the cos of x for the dilated triangle = 8/17

B is to c and f is to h

Explanation:

I've tooken this test like 12 years ago