Freee point for you guys ¯\_(ツ)
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Ответ:
nicely
Explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
Ответ:
thx bro
Explaonation:
2+4= 6
:3
Ответ:
The Harlem Reinaissance was a cultural, intellectual and social movement developed in the decade of the 1920s in New York. It importance relies on the fact that it was considered the rebirth of African American cultural expressions. The so-called negro culture acquired great popularity.
Through the movement, African Americans who participated on it felt empowered again after a very long time, and found the strength to fight against constant discriminations and racist manifestations in everyday life.