Mathematics: 0.6(5+0.9-0.009)=a.35.346b.3.5346c.353.46d.3532.6

Step-by-step explanation:GivenAverage velocity is given by Now, equate the average and instantaneous velocity...

0.6(5+0.9-0.009)=a.35.346b.3.5346c.353.46d.3532.6 - id065090009353463534635346353261912227, aidentrooper8629

Ответ:

lexipiper8296

31.12.2021

Mathematics

According to the question; we are required to evaluate the expression;

0.6(5 + 0.9 - 0.009) = 3.5346

This can be done by solving the expression in the parenthesis first as follows;

(5 + 0.9 - 0.009)(5.9 - 0.009)(5.891)

We can then multiply 5.891 by 0.6 which yields;

0.6 × 5.891

= 3.5346.

Therefore, the expression 0.6(5 + 0.9 - 0.009) = 3.5346

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Ответ:

sbudlove2838

31.12.2021

Mathematics

3.5346

Step-by-step explanation:

0.6(5+0.9-0.009)

=0.6 x 5.831

=3.5346

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Ответ:

ally3724f

27.11.2020

Mathematics

$\dfrac{16}{9}\ s$

Step-by-step explanation:

Given

$s(t)=-t^3+2t^2+\frac{3}{2}$

Average velocity is given by

$v_{avg}=\dfrac{\int vdt}{\int dt}$

$v_{avg}=\dfrac{-\frac{t^4}{4}+\frac{2}{3}t^3+1.5t}{t}\\\\v_{avg}=-\frac{t^3}{4}+\frac{2}{3}t^2+1.5$

Now, equate the average and instantaneous velocity

$-\frac{t^3}{4}+\frac{2}{3}t^2+1.5=-t^3+2t^2+1.5\\\\\Rightarrow -\dfrac{3t^3}{4}+\dfrac{4t^2}{3}=0\\\\\Rightarrow t^2\left(-\dfrac{3}{4}t+\dfrac{4}{3}\right)=0\\\\\Rightarrow t=\dfrac{16}{9}\ s$

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0.6(5+0.9-0.009)=
a.35.346
b.3.5346
c.353.46
d.3532.6

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