(05.03 mc)
if x = 39, y = 58, and the measure of ac = 4 units, what is the difference in length between segments ab and ad? round your answer to the nearest hundredth.
triangles abc and adc in which angle c is a right angle, point d is on segment bc between points b and c, the measure of angle abd is x degrees, and the measure of angle adc is y degrees
.74 units
1.17 units
1.64 units
2.14 units

1.64 units

Step-by-step explanation:

step 1

Find the measure of AB

In the right triangle ABC

sin(x)=AC/AB

AB=AC/sin(x)

substitute the given values

AB=4/sin(39°)=6.36 units

step 2

Find the measure of AD

In the right triangle ADC

sin(y)=AC/AD

AD=AC/sin(y)

substitute the given values

AD=4/sin(58°)=4.72 units

step 3

Find the difference in length between segments AB and AD

AB-AD=6.36-4.72=1.64 units

Is this a real question? Lol,

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