Mathematics: 1/2s + 3/4s + 1/4s + 4 show work pls

First, rewriteNow, differentiate both sides using the chain rule:...

1/2s + 3/4s + 1/4s + 4 show work pls - id123414411944350, amanuelwold

Ответ:

mmoreno8041

17.04.2021

Mathematics

i think that it would be 1/5 but i dont have work to show. ;-;

Step-by-step explanation:

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Ответ:

HaydenSturgis1

17.04.2021

Mathematics

4 + 3s/2

Step-by-step explanation:

3/4s + 1/4s = 4/4s = 1s

First add the fraction with the same denominator & combine like terms

Then add 1/2s + 1s

Which equals

1/2 + 1 = 3/2 or 1.5

At last since 4 doesn’t have a variable(s) you cannot combine it so it’s stays the same

4 + 3s/2

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Ответ:

leo4687

04.01.2022

Mathematics

First, rewrite

$x^y=e^{\ln x^y}=e^{y\ln x}$

$5^{x-y}=e^{\ln5^{x-y}} = e^{\ln(5)(x-y)}$

Now, differentiate both sides using the chain rule:

$\dfrac{\mathrm d\left(e^{y\ln x}\right)}{\mathrm dx}=\dfrac{\mathrm d\left(e^{\ln(5)(x-y)}\right)}{\mathrm dx}$

$e^{y\ln x}\dfrac{\mathrm d(y\ln x)}{\mathrm dx}=e^{\ln(5)(x-y)}\dfrac{\mathrm d(\ln(5)(x-y))}{\mathrm dx}$

$x^y\left(\dfrac{\mathrm dy}{\mathrm dx}\ln x+y\dfrac{\mathrm d(\ln x)}{\mathrm dx}\right)=\ln(5)5^{x-y}\left(\dfrac{\mathrm d(x)}{\mathrm dx}-\dfrac{\mathrm dy}{\mathrm dx}\right)$

$x^y\left(\ln x\dfrac{\mathrm dy}{\mathrm dx}+\dfrac yx\right)=\ln(5)5^{x-y}\left(1-\dfrac{\mathrm dy}{\mathrm dx}\right)$

$\left(x^y\ln x+\ln(5)5^{x-y}\right)\dfrac{\mathrm dy}{\mathrm dx}=\ln(5)5^{x-y}-yx^{y-1}$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\ln(5)5^{x-y}-yx^{y-1}}{x^y\ln x+\ln(5)5^{x-y}}$

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1/2s + 3/4s + 1/4s + 4 show work pls

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