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reyesortiz6955

reyesortiz6955

29.10.2020 •

Mathematics

1. 7x- 7 =
2 X3-8 =
3.5x2-10x3 =
4. x² + 5x+4 =
5. 2x2-X-10 =

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Ответ:

mooreadrian412

28.11.2020

Girl search this up on google

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Ответ:

sammypaige08

28.11.2020

1: 7(x-1) 2: idk 3: -20 4: (x+4)x(x+1) 5: -6-x Hope it helps :)

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Ответ:

homework1911

23.01.2022

y = 4*5^x

Step-by-step explanation:

Given

$(x_1,y_1) = (-3,\frac{4}{125})$

(x_2,y_2) = (1,20)

Required

Determine the exponential equation

An exponential equation is of the form: y = ab^x

In: (x_2,y_2) = (1,20)

20 = ab^1

20 = ab ---- (1)

In: $(x_1,y_1) = (-3,\frac{4}{125})$

$\frac{4}{125} = ab^{-3}$ --- (2)

Divide (1) by (2)

$20/\frac{4}{125} = \frac{ab}{ab^{-3}}$

$20/\frac{4}{125} = b^4$

$20*\frac{125}{4} = b^4$

5*125 = b^4

625 = b^4

Take 4th roots of both sides

$\sqrt[4]{625} = b$

5 = b

b = 5

Substitute b = 5 in 20 = ab

20 = a * 5

Solve for a

a = 20/5

a = 4

Hence, the equation is:

y = 4*5^x

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