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kassandramarie16
25.03.2021 •
Mathematics
1. Each of these cans holds 200 cm. Find the heights of these two cans,
What are the heights of the 2 cm - radius can and the 5 cm - radius can respectively?
A
8 cm and 19 cm
B
13.79 cm and 2.45 cm
С
4.0 cm and 25.0 cm
D
15.9 cm and 2.5 cm
Solved
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Ответ:
If in rectangular coordinates we have a point (x, y), then the angle defined between the x-axis and a ray that connects the point with the origin is defined by:
Tan(θ) = y/x
Cos(θ) = x/(√(x^2 + y^2))
Sin(θ) = y/(√(x^2 + y^2))
Ctg(θ) = x/y
Sec(θ) = √(x^2 + y^2)/x
Csc(θ) = √(x^2 + y^2)/y
Ok, now we have all the equations.
We know that:
Sec(C) = 30/24
Then:
√(x^2 + y^2) = 30
x = 24
Replacing x in the first equation we get:
√(24^2 + y^2) = 30
y = √(30^2 - 24^2) = 18
Then we have:
x = 24
y = 18
√(x^2 + y^2) = 30
So we can just replace these in the equations:
Tan(C) = y/x = 18/24
Cos(C) = x/(√(x^2 + y^2)) = 24/30
Sin(C) = y/(√(x^2 + y^2)) = 18/30
Ctg(θ) = x/y = 24/18
Sec(θ) = √(x^2 + y^2)/x = 30/24
Csc(θ) = √(x^2 + y^2)/y = 30/18