DeanWhinchester8970
17.09.2019 •
Mathematics
1. if m< 1 = 7x + 6 and m2 2 = 8x – 6, find the value of x so that p is
perpendicular to q.
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Ответ:
7x + 6 =8x - 6
x= 12
Step-by-step explanation:
put them equal to each other then subtract 8x from both sides7x(-8x) + 6 = 8x(-8x) - 6to get -1x-1x + 6 = -6then subtract 6 from both sides-1x +6(-6) = -6(-6)you'll get -1x = -12then divide -1 to both sides-1x/-1 = -12/-1then you get x = 12Ответ:
1. 45/3
2. 18/3
3.480/5