1. in parallelogram efgh, the measure of angle f is (3x − 10)° and the measure of angle g is (5x + 22)°. what is the measure of angle g? 42° 53° 117° 127° 2. abcd is a parallelogram with diagonal ac. if the measure of angle cab is 21° and the measure of angle adc is 125°, what is the measure of angle dac? parallelogram abcd with diagonal ac; the measure of angle adc is 125 degrees, and the measure of angle cab is 21 degrees. 73° 62° 42° 34° can you show how to solve as well? you.

1.

Since we have parallelogram EFGH, we also know that EF║GH.

Therefore:

∠F + ∠G = 180°

(3x − 10)° + (5x + 22)° = 180°

3x + 5x - 10° + 22° = 180°

8x + 12°                  = 180°

8x                           = 180° - 12° = 168°

x                             = 168°/8 = 21°

Now use the new value of x to calculate angle G:

(5 · 21 + 22)° = 127°

2.

Since we have parallelogram ABCD, we also know that AB║CD

Therefore:

∠ADC + ∠DAB = 180°

∠ADC + (∠CAB + ∠DAC) = 180°

125° + (21° + ∠DAC) = 180°

∠DAC                       = 180° - 21° - 125°

∠DAC                       = 34°

A)

Step-by-step explanation:

V=1/3(r²)h

3* V=1/3(πr²h)*3 to get rid of the 1/3 on that side

3V/(πr²)=(πr²)h/(πr²) to get rid of the πr² on the other side(they cancel out)

3V/(πr²)=h is the final answer so that matches A