(1 point) Find the volume of the parallelepiped with one vertex at (4,2,4), and adjacent vertices at (6,3,8), (6,1,10), and (0,6,3)

8 cubic units

Step-by-step explanation:

Let he vertices of the parallelepiped be A = (4,2,4), B= (6,3,8), C = (6,1,10) and D =  (0,6,3)

The edges of the parallelepiped are

AB = (6,3,8)  - (4,2,4) = (2,1,4)

AC = (6,1,10) - (4,2,4) = (2,-1,6)

AD = (0,6,3) - (4,2,4) = (-4,4,-1)

Therefore the volume of the parallelopiped is = |[AB,AC,AD]|

=  

= |2(1-24)+1(-2+24)+4(8-4)|

= |2(-23) + 1(22) + 4(4)|

= |8|

=8 cubic units

Step-by-step explanation:

The complete question in the attached figure

we know that

The center of the given circle in the figure is the point (4,5)

Remember that

The equation of a circle is

where

(h,k) is the center

r is the radius

For r=2 units

substitute