bree9362

22.07.2019 • 

Mathematics

1. solve the system using substitution (1 point) x + y = 8 y = 3x (a). (4, 12) (b). (2, 6) (c). (1/2, 3/2) (d). (-4, -12) 2. solve the system using substitution (1 point) 2x + 2y = 38 y = x + 3 (a). (8, 11) (b). (4, 7) (c). (35/4, 47/4) (d). (-4, -7) 3. solve the system using substitution (1 point) y = 8 - x 7 = 2 - y (a). (5, 13) (b). (13, -5) (c). (3, 5) (d). (21, -13) 4. solve the system using substitution (1 point) 3x + 2y = 23 1/2x - 4 = y (a). (9, -2) (b). (27/4, -5/8) (c). (31/4, -1/8) (d). (3/2, -13/4) 5. solve the system using substitution (1 point) y - 2x = 3 3x - 2y = 5 (a). (-1/2, 2) (b). (2, 7) (c). (-8, -13) (d). (-11, -19) unit 7 lesson 2, solving systems using substitution. if you completed this algebra lesson yet give me the rest of the : )

Ответ:

liamhallowell28

14.03.2022

Mathematics

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I'll do the first two so that you can try and practice them on your own.

1.

y = 3x, let's input that into the other equation.

x + 3x = 8
4x = 8
Divide both sides by 4.
x = 2

y = 3(2)
y = 6

(2, 6)

2.

y = x + 3, let's input that into the other equation.

2x + 2(x + 3) = 38
2x + 2x + 6 = 38
Subtract 6 from both sides.
4x = 32
Divide both sides by 4.
x = 8

y = 8 + 3
y = 11

(8, 11)

Good luck!

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Ответ:

datgamer13

26.10.2022

Mathematics

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(12,5) (3, -9) (3,14) (-6,5)

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