josebrown521
22.11.2020 •
Mathematics
1) Solve this system of linear equations by elimination.
2x+4y=8
3x=12+4y
*x=4,y=0
*x=3,y=1
*x=3,y=0
*x=4,y=1
please answer step by step
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Ответ:
Step-by-step explanation:
2x+4y=8
3x-4y=12
2x+4y+3x-4y=8+12
cancel +4y and -4y
therefore 2x+3x=20
5x=20
x=20/5
x=4
Sibstituting x=4 in 2x+4y=8
2x+4y=8
2*4+4y=8
8+4y=8
4y=8-8
y=0/4
y=0
x=4
y=0
Ответ:
Step-by-step explanation: