1. There are 10 people in a math club. Three people will be chosen for the Pi Day committee. How many different ways can club members structure the committee? a. 12 b. 120 c. 720 d. 604,800

120

Step-by-step explanation:

From the question, we are informed that there are 10 people in a math club and that three people will be chosen for the Pi Day committee.

The number of different ways that the club members can structure the committee goes thus:

This can be solved by:

nCr = n! / r! (n - r)!

where n = 10

r = 3

= n! / r! (n - r)!

= 10! / 3! (10 - 3)!

= (10 × 9 × 8) / (3 × 2)

=120

The ratio is 4:5
so girls=4x
and boys=5x
(because you don't know how many boys or girls there are)
then the equation would be
4x+5x=18
9x=18
so x=2
 then 2 times 4 which equals 8
and 2 times 5 which equals 10

so there are 8 girls and 10 boys