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edsimms21111
21.03.2020 •
Mathematics
1. To approach the runway, a small plane must begin a 6° descent starting from a height of 1000 feet above the ground. To the nearest foot, how many feet from the runway is the airplane at the start of this approach?
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Ответ:
The plane was 9514 ft. distant from the runway.
Step-by-step explanation:
See the attached diagram.
Now, B is the initial position of the plane which is 1000 ft. above A.
Now, Δ ABC is a right triangle having ∠ ACB = 6°
So, applying trigonometry, we can write
⇒ x = 9514.36 ≈ 9514 ft.
Therefore, the plane was 9514 ft. distant from the runway. (Answer)
Ответ:
let how answer
Step-by-step explanation:
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