Mathematics: 1. use the quadratic formula to solve the equation. -2x^2+3x+5=0

1. use the quadratic formula to solve the equation.

Ответ:

dmgcity

01.01.2022

The formula for the solution is:
$x=\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your case: a=-2, b=3, c=5

Replace these in the formula and you'll get:
$x_1=\frac{-b + \sqrt{b^2 - 4ac}}{2a}=\frac{-3 + \sqrt{3^2 - 4 \cdot (-2) \cdot 5}}{2 \cdot (-2)}=-1$
$x_2=\frac{-b - \sqrt{b^2 - 4ac}}{2a}=\frac{-3 - \sqrt{3^2 - 4 \cdot (-2) \cdot 5}}{2 \cdot (-2)}= \frac{5}{2}$

So you have two roots:
x1 = -1
x2 = 5/2

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Ответ:

calderonjudith9351

06.02.2023

Mathematics

3x+5y=1
7x+4y=-13
3x=1-5y
x=1/3-(5/3)y
7(1/3-5/3y)+4y=-13
7/3-35/3y+4y=-13
-23/3y+7/3=-13
-23/3y=-46/3
y=2

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1. use the quadratic formula to solve the equation. -2x^2+3x+5=0

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