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smortandsons
24.10.2021 •
Mathematics
1/x+2 - 1/x-2 = 1
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Ответ:
Given equation is 1/(x+2) - 1/(x-2) = 1
=> [(x-2)-(x+2)]/(x+2)(x-2) = 1
=> (x-2-x-2)/(x²-4) = 1
=> (-2-2)/(x²-4) = 1
=> -4/(x²-4) = 1
=> x²-4 = -4
=> x²-4+4 = 0
=> x² +0 = 0
=> x² = 0
The standard form is x² = 0 or x²+0x+0 = 0
Here I have used this formulae in your all questions.
The standard quadratic equation is ax²+bx+c = 0
Hope this helps!!
Ответ:
31/40
63/80
Step-by-step explanation: