10 ptsif the area of the frame was 64 inches², what would be 2 possible sets of dimensions that could be used to make a frame with that area? set 1: set 2: show your work/explain your thinking:

Possible dimensions are 16 × 4 inches and 32 × 2 inches.

Step-by-step explanation:

We are given that,

Area of the frame = 64 inch² = Length × Width

Now, we have that 64 can be factored as,

64 = 32 × 2

64 = 16 × 4

64 = 8 × 8

Since, the frame is in a rectangular shape. So, we reject the possibility of 8 × 8 inches frame.

Thus, the possible dimensions are,

Set 1: 16 × 4 inches

Set 2: 32 × 2 inches.

volume cone = 1/3 pi r^2 h

volume cylinder = pi r^2 h

Step-by-step explanation:

1.  Volume = 1/3 x pi x r^2 x h = 12 X pi

2.  100 pi = 1/3 x pi x r^2 x 12

r^2 = 25

r = 5 cm

3.  volume = pi x 16 X 5 = 80 pi cubic meters

4.  400 pi = pi x r^2 X 4

r^2 = 100

r = 10 yards