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lakeshia8880
17.01.2020 •
Mathematics
100 - 99 + 98 - 97 + 96 ect formula
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Ответ:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number
Since a=100 and d=-1 we have:
a(n)=100-1(n-1), which we can simplify as:
a(n)=100-n+1
a(n)=101-n
Now the only thing that we need to correct is to have the signs of the numbers alternate between positive and negative.
Since the first term is positive, we could say -1^(n+1). This expression will start out positive and will alternate back and forth from then onward. Now we simply have to multiply our sequence by this coefficient...
a(n)=-1^(n-1)*(101-n)
The above will produce the sequence you have listed
Ответ:
Step-by-step explanation: