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WANEES13
26.10.2020 •
Mathematics
11. A pizza parlor has four types of crust, 12 different toppings, and three different cheese blends to choose from. In how many ways could you order a three-topping pizza (one type of crust, three different toppings, and one cheese blend)
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Ответ:
1320
Step-by-step explanation:
Given: In pizza parlor, Number of types of crust = 4
Number of types of different toppings = 12
Number of types of cheese blends = 3
Now, the number of ways to choose a pizza with one type of crust, three different toppings, and one cheese blend
=
=![4\times \ \dfrac{12!}{3!(12-3)!}\times 3\ \ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!},\ ^nC_1=n]](/tpl/images/0840/4566/8dec5.png)
=![12\times\dfrac{12\times11\times10\times9!}{2\times6\times9!}](/tpl/images/0840/4566/7e923.png)
=![12\times11\times10= 1320](/tpl/images/0840/4566/1a48b.png)
Hence, the required number of ways = 1320
Ответ:
30 cents
Step-by-step explanation:
2 dozen : $7.20
24 cookies : $7.20
/24 /24 (to find unit price)
1 cookie : 30 cents
btw it sounds like your using a math book. slader.com has a bunch of math books answer keys (i wasn't told to promote the btw)