12 Given that the lines 3x+4y+6=0 and 4x-
qy+3=0 are perpendicular, find the value
of q. *
(1 Point)

q = 3.

Step-by-step explanation:

They are perpendicular so  the product of their slopes = -1.

3x + 4y + 6 = 0

4y = -3x - 6

y = -3/4 x - 3/2

- so the slope of this line is -3/4 which makes the slope of the other line equal to - / -3/4  = 4/3.

4x - qy = -3

-qy = -4x - 3

qy = 4x + 3

y = 4/q x + 3/q

So as the slope is 4/3, we have:

4/q = 4/3

Therefore q = 3.

good question

Step-by-step explanation:

im wondering the same thing XD