(15 points) Please help! Last two pre algebra questions! Will mark brainliest

Step-by-step explanation:

1. slope=-3/2-3 is at the top,2 is at the bottom

y intercept=4-The y intercepts or goes past at 4,

equation=y=-3/2+4-We put it all together and we get y=-3/2+4!

2. slope=-3/2-It starts at 3 again,and ends at two again.

y intercept=0-The y touches the line at 0,or the middle

equation=y=-3/2-y equals the slope and we subtract y.

To solve for the value of the residues A, we can use the formula:

A^2 = 1                 (mod prime)

This is only true for prime numbers. The given number which is 317 is a prime number therefore the values of the residues A are:

A = + 1, - 1

Since I believe the problem specifically states for the list of positive integers only and less than 317, a value of A = - 1 is therefore not valid. However, a value of – 1 in this case would simply be equal to:

317 – 1 = 316

Therefore the residue values A are 1 and 316.