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ezy53
21.01.2021 •
Mathematics
15) The velocity of a particle moving along the x-axis is given by v(t)=sin(4t) at time t. If the particle is at x=6 at t=0, what is the position of he particle at =8 ?
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Ответ:
b] the angles created by this intersection between c and d are special because they are equal to each other, to solve for y we shall have:
(5y-29)=(3y+19)
this is because they are vertical angles, hence solving the above we get:
5y-3y=19+29
2y=48
y=48/2
y=24°
c] to solve for ∠7 and ∠8 we proceed as follows;
angles in a straight line add up to 180:
therefore:
(5y-29)+∠7=180
substituting the value of y in the above and solving for ∠7 we get:
(5×24-29)+∠7=180
91+∠7=180
∠7=180-91
∠7=89
but remember that vertical angles are equal to each other, therefore:
∠7=∠8=89°