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nicolasjarrin
25.04.2020 •
Mathematics
2 2/5 x 4 = {Khan Academy}
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Ответ:
9.6 or 9 and 3/5
Step-by-step explanation:
turn 2 and 2 fifths into an improper fraction and multiply by four
Ответ:
Minimum number of pennies = 10
Step-by-step explanation:
Given:
Maximum number of coins Hannah have = 25
Total number of of nickels (coins) she has = 11
Total value of the combined coins = $ 0.65
We have to find the minimum number of pennies.
Let the number of pennies be "p" and no. of nickels be "n".
Note:
Value of 1 penny = $ 0.01
Value of 1 nickel = $ 0.05
Arranging the above situation in terms of equations:
According to their quantities.
⇒
and
so ![p\leq 14](/tpl/images/0610/4623/2024f.png)
According to their values.
⇒![0.05(n)+0.01(p)\leq \$\ 0.65](/tpl/images/0610/4623/d4a39.png)
⇒![0.05(11)+0.01(p)\leq \$\ 0.65](/tpl/images/0610/4623/c115c.png)
⇒![\$\ 0.55+0.01(p)\leq \$\ 0.65](/tpl/images/0610/4623/c4c0c.png)
⇒![0.01(p)\leq \$\ 0.65-\$\ 0.55](/tpl/images/0610/4623/f7cd9.png)
⇒![0.01(p)\leq \$\ 0.10](/tpl/images/0610/4623/ac7eb.png)
⇒![(p)\leq\frac{ \$\ 0.10}{0.01}](/tpl/images/0610/4623/b7513.png)
⇒![(p)\leq 10](/tpl/images/0610/4623/d18a4.png)
Minimum number of pennies :
⇒
which also satisfies ![p\leq 14](/tpl/images/0610/4623/2024f.png)
Therefore :
⇒![p=10](/tpl/images/0610/4623/1d9ee.png)
Plugging p= 10 we can verify the values.
⇒![0.05(11)+0.01(10)\leq \$\ 0.65](/tpl/images/0610/4623/c983d.png)
⇒![0.55+0.10\leq \$\ 0.65](/tpl/images/0610/4623/66100.png)
⇒![\$\ 0.65\leq \$\ 0.65](/tpl/images/0610/4623/ce8b6.png)
So,
Minimum number of pennies Hannah have = 10