2^2x - 6(2^x) + 5 = 0

can you please write the expression with the mathematical symbols. I can't understand what you mean by (^). do you mean that number is raised to that symbol or are you're trying to multiply. if you don't know how to write exactly how it's given, attach a picture of your question.

Step-by-step explanation:

2x2 + 6x - 5 = 0.

2x2 + 6x = 5.

The method of completing the square demonstrated in the previous example only works if the leading coefficient (coefficient of x2) is 1. In this example the leading coefficient is 2, but we can change that by dividing both sides of the equation by 2.

x2 + 3x = 5/2.

Now that the leading coefficient is 1, we take the coefficient of x, which is now 3, divide it by 2 and square, (3/2)2 = 9/4. This is the constant that we add to both sides to complete the square.

x2 + 3x + 9/4 = 5/2 + 9/4.

The left hand side is the square of (x + 3/2). [ Verify this!]

(x + 3/2)2 = 19/4.

Now we use the square root principle and solve for x.

x + 3/2 = ± sqrt(19/4) = ± sqrt(19)/2.

x = -3/2 ± sqrt(19)/2 = (-3 ± sqrt(19))/2

Step-by-step explanation:

The equation is x - y = 8

Rewrite it into the format y = mx + b
⇒ x - y = 8
⇒ y = x - 8

Compare y = x - 8 with y = mx + b
⇒ m = 1, therefore slope = 1

Slope of the perpendicular line = -1 (negative reciprocal )

-1