(-2,3)
find tan cos sin

Given thing are

cos Θ = 2/3

we know that Cos Θ = Adjacent Side / Hypotenuse, so we get

Adjacent Side = 2

Hypotenuse = 3

Hypotenuse : BC = 3

Adjacent Side : AB = 2 (Adjacent to ∠ Θ)

Opposite Side : AC = ? (Opposite to ∠ Θ)

To find the Opposite Side - AC , we use Pythagoras theorem ((Hypotenuse)2 = (Leg 1)² + (Leg 2)²)

AC = √ BC² - AB²

AC = √ 32 - 22

AC = √ 9 - 4

AC = √5

Now we will try to simplify square root of 5. As no pairs can be made the final value will be

__

AC = √ 5

So Sin, Cos and Tan will be as follows -

Sin Θ = Opposite Side / Hypotenuse

__

Sin Θ = √5/3

Tan Θ = Opposite Side / Adjacent Side

__

Tan Θ = √5/2

Cos Θ = Adjacent Side / Hypotenuse

Cos Θ = 2/3