2. {5.0A.A.1, 5.0A.A.2} Write an expression to showthe product of eight
and two, minus the product of three and four. *

Let the number of red, black, green and blue balls be R, B, G, U respectively.

B=R  (There are as many black balls as red balls)

G+R=10 so G=10-R (Green balls and red balls should add up to 10)

R+10=U (There should be 10 more blue balls than red balls)

The minimal number of balls is 2, 304 so we have the following inequality:

R+B+G+U≥ 2,304

R+(R)+(10-R)+ (R+10)≥2,304

4R≥2,304

R≥2,304/4=576 so R=576

576