Mathematics: 2. from the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. find the angle of depression to the objeci. a) 34° b ) 940 c ) 104 degrees d) 540

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2. from the top of a vertical cliff 40 m high, the - id2403658017, michelejoantucker

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NEUROPHARMACOLOGICAL

09.01.2022

Mathematics

$34^{\circ}$ is the angle of depression from the vertical cliff.

Option: A

Step-by-step explanation:

Given that, Height of the cliff (opposite side) = 40m

Distance of object from the base of the cliff (adjecent side) = 59.3m

To find the angle of depression of the object. From trigonometric rule in a right angled triangle, we know that $\tan \theta=\frac{\text { opposite side }}{\text { adjecent side }}$ $\theta=\tan -1 \frac{\text { opposite side }}{\text { adjecent side }}$ Angle of depression = $\tan -1 \frac{\text { height of cliff }}{\text { Distance of object from the base of the cliff }}=\tan ^{-1} \frac{40}{59.3}=34^{\circ}$ Therefore, the angle of depression to the object is $34^{\circ}$ .

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2. from the top of a vertical cliff 40 m high, the object is 59.3m from the base of the cliff. find the angle of depression to the objeci. a) 34° b ) 940 c ) 104 degrees d) 540

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