tashaunalewis6774
19.05.2020 •
Mathematics
2 ( n-1 ) + 4n= 2( 3n-1 )
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Ответ:
infinite solutions
Step-by-step explanation:
2 ( n-1 ) + 4n= 2( 3n-1 )
Distribute
2n -2 +4n = 6n -2
Combine like terms
6n -2 = 6n -2
Subtract 6n from each side
6n-2-6n = 6n-2-6n
-2 = -2
This is always true so there are infinite solutions
Ответ:
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