2. The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet.
Find the width of the rectangle.

In order to solve this let us for at assume that the value of the width is X. Therefore the length will be x+5.

We can now write an equation:

(X+5) + (X+5) + X + X = 58

Combining like terms we should get
4X + 10 = 58

Now subtract 10 from both sides to get
4x = 48

Divide by 4 now and you should get

X = 12

Now we know the value of X and therefore the width.

570.332 is the answer