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luckilyalexa
03.01.2020 •
Mathematics
$23,803 is invested, part at 8% and the rest at 5%. if the interest earned from the amount invested at 8% exceeds the interest earned from the amount invested at 5% by $357.89, how much is invested at each rate? (round to two decimal places if necessary.)
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Ответ:
The amount invested at 8% is $11,908 and the amount invested at 5% is $11,895
Step-by-step explanation:
Let
x ----> the amount invested at 8%
(23,803-x) ----> the amount invested at 5%
Remember that
we know that
The interest earned from the amount invested at 8% is equal to the interest earned from the amount invested at 5% plus $357.89
so
The linear equation that represent this situation is
solve for x
Apply distributive property right side
Group terms
Combine like terns
therefore
The amount invested at 8% is $11,908 and the amount invested at 5% is $11,895
Ответ:
L = 2W + 4
P 38
2(2W+4 + W) = 38
4W + 8 + 2W = 38
6W + 8 = 38
6W = 38 - 8
6W = 30
W = 30/6 = 5the greatest possible value is 5