2k^2-5k-18=0 what is both of the values of k? plz ! 15 !

To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)

The answer is 2

Step-by-step explanation:The degree is the little number on the top of the x . when the other numbers dont have any, it is an invisible 1 so by that, x has the highest.