Mathematics: 2ln(4x –7) –1=11 solve for x to the nearest 100th

2ln(4x –7) –1=11 solve for x to the nearest 100th

Ответ:

heyyyyy39

22.10.2020

$SQ\not=2OM\\\\Sam\ is\ not\ Correct.$

Step-by-step explanation:

Pythagorean Theorem: In a right triangle the square of longest side(hypotenuse) is equal to the sum of the squares of the other sides.

$In\ \triangle SQR\\\\Hypotenuse=SQ\\\\SQ^2=QR^2+RS^2\\\\SQ^2=6^2+12^2\\\\SQ^2=180\\\\SQ^2=36\times 5\\\\SQ^2=6^2\times 5\\\\SQ=6\sqrt{5}\approx 13.42$

$In\ \triangle OLM\\\\Hypotenuse=OM\\\\OL=LM=6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Sides\ of\ a\ square\\\\OM^2=OL^2+LM^2\\\\OM^2=6^2+6^2\\\\OM^2=72\\\\OM=6\sqrt{2}\approx 8.49$

$2\times OM=16.97SQ\\\\\Rightarrow SQ\not=2OM\\\\Sam\ is\ not\ Correct$

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2ln(4x –7) –1=11 solve for x to the nearest 100th

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