Mathematics: 2x^2-5x+2=0 quadratic formula

4. Vertical angles theorem 6. 3x + 4 =49Step-by-step explanation:...

2x^2-5x+2=0 quadratic formula - id225203910999, yedida

bludragonfly33

10.01.2022

The solutions are $x_{1}=2\ and\ x_{2}=0.5$ .

Step-by-step explanation:

Given:

$2x^{2} -5x+2=0$

Now, to solve by using quadratic formula:

$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

Here $a=2,b=-5\ and\ c=2$

$x=\frac{-(-5)\pm \sqrt{(-5)^{2}-4\times 2\times 2}}{2\times 2}$

Now, here we will take either $x=\frac{-(-5)+\sqrt{25-16}}{4}$ and then $x=\frac{-(-5)-\sqrt{25-16}}{4}$ .

$x=\frac{-(-5)+\sqrt{25-16}}{4}$ $x=\frac{-(-5)-\sqrt{25-16}}{4}$

$x=\frac{5+\sqrt{9}}{4}$ $x=\frac{5-\sqrt{9}}{4}$

$x=\frac{5+3}{4}$ $x=\frac{5-3}{4}$

$x=\frac{8}{4}$ $x=\frac{2}{4}$

$x_{1}=2$ $x_{2}=\frac{1}{2}=0.5$

Therefore, the solutions are $x_{1}=2\ and\ x_{2}=0.5$ .

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