2x+3x+1=21
Solve and show work

x=4

Step-by-step explanation:

2x+3x+1=21

(2x+3x)+(1)=21

5x+1=21

5x+1=21

Step 2: Subtract 1 from both sides.

5x+1−1=21−1

5x=20

Step 3: Divide both sides by 5.

x=4

Step-by-step explanation:

2x+3x+1=21

Simplify both sides of the equation.

2x+3x+1=21

(2x+3x)+(1)=21(Combine Like Terms)

5x+1=21

5x+1=21

Subtract 1 from both sides.

5x+1−1=21−1

5x=20

Divide both sides by 5.

5x /5 = 20 /5

x=4

Shania is correct.

Step-by-step explanation:

For a right angled triangle, given two sides and an angle, we can use the sine rule or the various trigonometry identities to solve the triangle;

a/sin A = b/sinB

and

sin (angle) = opposite side/hypotenuse

cos (angle) = adjacent side/hypotenuse

tan (angle) = opposite/ adjacent

assuming a is the opposite side of angle A and b is also opposite of angle B

Otherwise, the only way to solve a triangle given two sides only is by the use of the Pythagoras theorem.

Hence, Shania is correct.