Mathematics: (2x-y)(3x+y) a 6x^2 – xy – y^2 b 5x^2 – xy – y^2 c 6x^2 – xy – 2y^2 d 5x^2 – xy – 2y^2

5-3 5 3 20 3 __= _-_ = __-__= 4 1 4 4 4 17 ___ 4 I divide it the number to get the same denominator and do it on the top too....

(2x-y)(3x+y) a 6x^2 – xy – y^2 b 5x^2 – xy – y^2

stefancvorovic1

10.01.2022

For this case we must solve the following product:

(2x-y) (3x + y) =

We apply distributive property considering that:

$+ * + = +\\+ * - = -$

So:

(2x) (3x) + (2x) (y) - (y) (3x) - (y) (y) =

To multiply powers of the same base, the same base is placed and the exponents are added:

$6x^{1 + 1} + 2xy-3xy-y^{1 + 1} =$

Different signs are subtracted and the sign of the major is placed:

6x ^ 2-xy-y ^ 2

So, the solution is: 6x ^ 2-xy-y ^ 2

Option A

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