(3,16) and (6,19) if a problem has this written in it which ones would be x and which would be y? it says put it in this form. y=mx+b

The first numbers in the blakets are the "x" and the second numbers are "y"

3 is the x1 and 6 is x2

16 is y1 and 19 is y2

y=x+13

Step-by-step explanation:

in order to find slope

y2-y1/x2-x1          (x1,y1) = (3,16)   (x2,y2)= (6,19)

19-16/6-3= 3/3= 1

slope=1

Now using this equation y-y1=m(x-x1)

y-16=1(x-3)

now solve for y

distribute the right side

y-16=x-3

  +16   +16

y=x+13

3, 6, 9, 12

4, 8, 12

LCM = 12